{"id":18447,"date":"2024-04-07T18:22:12","date_gmt":"2024-04-07T18:22:12","guid":{"rendered":"https:\/\/soicau2027.minhngocxoso.com\/?p=18447"},"modified":"2024-04-07T18:22:12","modified_gmt":"2024-04-07T18:22:12","slug":"the-nao-la-soi-cau","status":"publish","type":"post","link":"https:\/\/baode3mien.com\/the-nao-la-soi-cau\/","title":{"rendered":"th\u1ebf n\u00e0o l\u00e0 soi c\u1ea7u ?"},"content":{"rendered":"
Soi c\u1ea7u l\u00e0 g\u00ec: Th\u00f4ng th\u01b0\u1eddng c\u00e1c b\u1ea1n ch\u01a1i l\u00f4 \u0111\u1ec1 ho\u1eb7c kh\u00f4ng ch\u01a1i l\u00f4 \u0111\u1ec1 nh\u01b0ng ch\u1eafc h\u1eb3n ai c\u0169ng nghe n\u00f3i \u0111\u1ebfn soi c\u1ea7u l\u00f4, soi c\u1ea7u \u0111\u1ec1. Th\u00ec h\u00f4m nay Admin s\u1ebd gi\u1ea3i th\u00edch cho c\u00e1c b\u1ea1n v\u1ec1 thu\u1eadt ng\u1eef n\u00e0y d\u00e0nh cho c\u00e1c anh em ch\u01b0a bi\u1ebft v\u1ec1 n\u00f3.<\/p>\n
Th\u00f4ng th\u01b0\u1eddng soi c\u1ea7u l\u00f4 hay soi c\u1ea7u \u0111\u1ec1 l\u00e0 thu\u1eadt ng\u1eef ch\u1ec9 c\u00e1ch k\u1ebft h\u1ee3p hai v\u1ecb tr\u00ed tr\u00ean b\u1ea3ng t\u1ed5ng so\u00e1t d\u00e0n s\u1ed1 quay ra ng\u00e0y h\u00f4m tr\u01b0\u1edbc v\u00e0 d\u1ef1 \u0111o\u00e1n k\u1ebft qu\u1ea3 d\u00e0nh cho ng\u00e0y h\u00f4m sau. Nh\u01b0 v\u1eady ch\u00fang ta c\u00f3 th\u1ec3 hi\u1ec3m l\u00e0 soi c\u1ea7u l\u00e0 soi x\u00e9t k\u1ebft qu\u1ea3 ng\u00e0y h\u00f4m tr\u01b0\u1edbc v\u00e0 d\u1ef1 \u0111o\u00e1n k\u1ebft qu\u1ea3 cho ng\u00e0y h\u00f4m nay.<\/p>\n
Khi soi c\u1ea7u mi\u1ec1n b\u1eafc b\u1ea1n ph\u1ea3i bi\u1ebft c\u00f3 bao nhi\u00eau v\u1ecb tr\u00ed trong b\u1ea3ng k\u1ebft qu\u1ea3. \u1ede gi\u1ea3i \u0111\u1eb7c bi\u1ec7t, I, II, gi\u1ea3i III c\u00f3 5 s\u1ed1. V\u1eady 10 gi\u1ea3i s\u1ebd c\u00f3 50 s\u1ed1.<\/p>\n
\u2013 40 s\u1ed1 g\u1ed3m 4 gi\u1ea3i t\u01b0 v\u00e0 6 gi\u1ea3i n\u0103m m\u1ed7i gi\u1ea3i c\u00f3 4 s\u1ed1, 3 gi\u1ea3i 6 v\u1eady c\u00f3 9 s\u1ed1. Gi\u1ea3i 7 c\u00f3 4 gi\u1ea3i, m\u1ed7i gi\u1ea3i 2 s\u1ed1 l\u00e0 8 s\u1ed1.<\/p>\n
=> Nh\u01b0 v\u1eady ta c\u00f3 t\u1ea5t c\u1ea3 50+40+9+8=107 s\u1ed1 t\u01b0\u01a1ng \u1ee9ng 107 v\u1ecb tr\u00ed kh\u00e1c nhau.<\/p>\n
\u2013 T\u1eeb \u0111\u1ecbnh ngh\u0129a v\u1ec1 c\u1ea7u l\u00f4 ta c\u00f3 th\u1ec3 hi\u1ec3u r\u1eb1ng, \u1edf m\u1ed7i v\u1ecb tr\u00ed c\u00f3 th\u1ec3 gh\u00e9p \u0111\u01b0\u1ee3c 106 v\u1ecb tr\u00ed kh\u00e1c nhau \u0111\u1ec3 t\u1ea1o th\u00e0nh 106 c\u1ea7u l\u00f4 kh\u00e1c nhau. Theo ph\u00e9p t\u00ednh giai th\u1eeba th\u00ec t\u1ed5ng s\u1ed1 c\u1ea7u l\u00f4 gh\u00e9p 2 v\u1ecb tr\u00ed kh\u00e1c nhau l\u00e0 [(107!)\/(107-2)! X 2!] = 5671.<\/p>\n
<\/p>\n
\u2013 Th\u00eam m\u1ed9t \u0111i\u1ec1u ng\u01b0\u1eddi ch\u01a1i c\u1ea7n ch\u00fa \u00fd l\u00e0 c\u00e1c v\u1ecb tr\u00ed kh\u00f4ng ch\u1ec9 gh\u00e9p v\u1edbi v\u1ecb tr\u00ed kh\u00e1c m\u00e0 c\u00f3 th\u1ec3 gh\u00e9p \u0111\u01b0\u1ee3c v\u1edbi ch\u00ednh n\u00f3 \u0111\u1ec3 c\u00f3 c\u1eb7p s\u1ed1 k\u00e9p. Nh\u01b0 v\u1eady ta l\u1ea1i c\u00f3 th\u00eam 107 c\u1ea7u l\u00f4 s\u1ed1 k\u00e9p n\u1eefa \u0111\u1ec3 \u0111\u00e1nh l\u00f4 \u0111\u1ec1.<\/p>\n
\u2013 Ngo\u00e0i ra c\u00f2n c\u00f3 c\u00e1ch gh\u00e9p t\u1eebng v\u1ecb tr\u00ed trong b\u1ea3ng k\u1ebft qu\u1ea3 v\u1edbi c\u00e1c s\u1ed1 t\u1ef1 nhi\u00ean t\u1eeb 0-9, c\u00f3 th\u00eam 107\u00d710=1070 c\u1ea7u l\u00f4 n\u1eefa. V\u1edbi c\u00e1ch gh\u00e9p n\u00e0y nhi\u1ec1u tr\u01b0\u1eddng h\u1ee3p ra c\u1ea7u l\u00f4 c\u1ef1c t\u1ed1t.<\/p>\n
\u2013 M\u1ecdi c\u00e1ch gh\u00e9p ta c\u00f3 5671 + 107 + 1070 = 6848 c\u1ea7u l\u00f4.<\/p>\n
\u0110\u1ec3 d\u00e0n \u0111\u1ec1 n\u00e0y ph\u00e1t huy hi\u1ec7u qu\u1ea3 th\u1ef1c s\u1ef1. Anh em c\u1ea7n \u0111\u00e1nh \u0111\u1ee7 khung 5 ng\u00e0y v\u1edbi t\u1ef7 l\u1ec7 v\u00e0o ti\u1ec1n t\u00f9y thu\u1ed9c v\u00e0o v\u1ed1n c\u1ee7a anh em. B\u00ean d\u01b0\u1edbi m\u00ecnh \u0111\u01b0a ra 2 ph\u01b0\u01a1ng \u00e1n v\u00e0o ti\u1ec1n \u0111\u1ec3 anh em t\u1ef1 c\u00e2n nh\u1eafc.<\/p>\n
Ph\u01b0\u01a1ng \u00e1n 1:<\/p>\n
N1 \u2013 10k\/s\u1ed1 = 400k nh\u1eadn 990k \u2013 L\u00e3i 590k<\/p>\n
N2 \u2013 30k\/s\u1ed1 = 1,200k nh\u1eadn 2,970k \u2013 L\u00e3i 1,370k<\/p>\n
N3 \u2013 70k\/s\u1ed1 = 2,800k nh\u1eadn 6,930k \u2013 L\u00e3i 2,530k<\/p>\n
N4 \u2013 150k\/s\u1ed1 = 6,000k nh\u1eadn 14,850k \u2013 L\u00e3i 4,450k<\/p>\n
N5 \u2013 300k\/s\u1ed1 = 12,000k nh\u1eadn 29,700k \u2013 L\u00e3i 7,300k<\/p>\n
Ph\u01b0\u01a1ng \u00e1n 2:<\/p>\n
<\/p>\n
N1 \u2013 20k\/s\u1ed1 = 800k nh\u1eadn 1980k \u2013 L\u00e3i 1,180k<\/p>\n
N2 \u2013 60k\/s\u1ed1 = 2,400k nh\u1eadn 5,940k \u2013 L\u00e3i 2,740k<\/p>\n
N3 \u2013 120k\/s\u1ed1 = 4,800k nh\u1eadn 11,880k \u2013 L\u00e3i 3,880k<\/p>\n
N4 \u2013 250k\/s\u1ed1 = 10,000k nh\u1eadn 24,750k \u2013 L\u00e3i 6,750k<\/p>\n
N5 \u2013 500k\/s\u1ed1 = 20,000k nh\u1eadn 49,500k \u2013 L\u00e3i 11,500k<\/p>\n
L\u01b0u \u00dd: B\u00ean d\u01b0\u1edbi l\u00e0 2 ph\u01b0\u01a1ng \u00e1n v\u00e0o ti\u1ec1n ch\u01a1i d\u00e0n \u0111\u1ec1 40s t\u00ednh theo t\u1ef7 l\u1ec7 1 \u0103n 99 ch\u01a1i online. Anh em h\u00e3y ch\u01a1i online \u0111\u1ec3 nh\u1eadn \u0111\u01b0\u1ee3c t\u1ef7 l\u1ec7 t\u1ed1t nh\u1ea5t nha. Ch\u01a1i b\u00ean ngo\u00e0i 1 \u0103n 70 ho\u1eb7c 80 s\u1ebd l\u00e3i \u00edt h\u01a1n.<\/p>\n
Soi c\u1ea7u l\u00f4 \u0111\u1ec1 l\u00e0 m\u1ed9t h\u00ecnh th\u1ee9c d\u1ef1 \u0111o\u00e1n tr\u01b0\u1edbc k\u1ebft qu\u1ea3 l\u00f4 \u0111\u1ec1 tr\u01b0\u1edbc gi\u1edd quay s\u1ed1 \u0111\u1ec3 t\u00ecm ra con s\u1ed1 ch\u00ednh x\u00e1c nh\u1ea5t cho gi\u1ea3i th\u01b0\u1edfng gi\u00fap ch\u00fang ta g\u1eb7t h\u00e1i \u0111\u01b0\u1ee3c th\u00e0nh c\u00f4ng nh\u1ea5t \u0111\u1ecbnh. Tr\u00ean \u0111\u00e2y l\u00e0 nh\u1eefng th\u00f4ng tin v\u1ec1 soi c\u1ea7u m\u00e0 c\u00e1c chuy\u00ean gia l\u00f4 \u0111\u1ec1 chia s\u1ebb \u0111\u1ebfn anh em n\u1ebfu anh em c\u00f3 ph\u01b0\u01a1ng ph\u00e1p n\u00e0o hay h\u01a1n ho\u1eb7c c\u00e1ch soi c\u1ea7u n\u00e0o t\u1ed1t h\u01a1n c\u00f3 th\u1ec3 chia s\u1ebb v\u1edbi ch\u00fang t\u00f4i b\u1eb1ng c\u00e1ch \u0111\u1ec3 l\u1ea1i b\u00ecnh lu\u1eadn d\u01b0\u1edbi b\u00e0i vi\u1ebft n\u00e0y nh\u00e9.<\/p>\n